Question

question no.5 i try but....

Answer 1

Hey!!!

Good Morning

Let's solve

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=> 1/(2x - 3) + 1/(x - 5) = 1

=> (x - 5) + (2x - 3)/(2x - 3)(x - 5) = 1

=> 3x - 8 = (2x - 3)(x - 5)

=> 3x - 8 = 2x² - 10x - 3x + 15

=> 2x² - 16x + 23 = 0

By Quadratic Formula,

$= > x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

=> x = (16 +- √256 - 8(23))/4

=> x = (16 +- √72)/4

Thus

=> x = (16 - 36√2)/4

Taking 16 common

=> x = (1 - 2√2) <<<<<<< Answer

Also

=> x = (1 + 2√2) <<<<<<<< Answer

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Hope this helps ✌️

Legally Good Morning

Answer 2

=> 1/(2x - 3) + 1/(x - 5) = 1
=> (x - 5) + (2x - 3)/(2x - 3)(x - 5) = 1
=> 3x - 8 = (2x - 3)(x - 5)
=> 3x - 8 = 2x² - 10x - 3x + 15
=> 2x² - 16x + 23 = 0
=> x = (16 +- √256 - 8(23))/4
=> x = (16 +- √72)/4
=> x = (16 - 36√2)/4

=> x = (1 - 2√2)