Math, asked by aksh3azirashinsi, 1 year ago

rang of 13cos(x) + 3√3 sin(x) - 4

Answers

Answered by abhi178
9
f (x) = 13cosx + 3 root3 sinx - 4

we know,
range of asinx + bcosx € [ -root (a^2 +b^2) , root (a^2 + b^2) ]

hence ,

13cosx + 3 root3 sinx €[-root (169+27) , root (169+27) ] = [ -14 , 14]


{13cosx + 3 root3 sinx -4 } €[ -18 , 10]

hence range € [ -18 , 10]
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