Question

rationalise the denominator of each of the following :ques:(1)6/3+√5.

Answer 1

6/3+√5
=6/3+√5×(3-√5)/(3-√5)
=6(3-√5)/(3)²-(√5)²
=6(3-√5)/9-5
=6(3-√5)/4
=3(3-√5)/2
=9-3√5/2

hope it helped...