rationalise the denominator of each of the following :ques:(1)6/3+√5.
Answers
Answered by
3
Rationalising denominator of 6/3+√5 -
(6/3+√5) × (3-√5/3-√5)
= 18-6√5 / (3)²-(√5)²
= (18-6√5)/9-5
= (18-6√5)/4
= 6(3-√5)/4
= 3(3-√5)/2
= (9-3√5)/2
(6/3+√5) × (3-√5/3-√5)
= 18-6√5 / (3)²-(√5)²
= (18-6√5)/9-5
= (18-6√5)/4
= 6(3-√5)/4
= 3(3-√5)/2
= (9-3√5)/2
Similar questions