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Given p(x) = 2x^4 - 5x^3 + 2x^2 - x + 2.
= > x^2 - 3x + 2
= > x^2 - 2x - x + 2
= > x(x - 2) - (x - 2)
= > (x - 1)(x - 2)
Now,
if p(1) and p(2) = 0, then p(x) is exactly divisible by f(x).
= > p(1) = 2(1)^4 - 5(1)^3 + 2(1)^2 - 1 + 2
= 2 - 5 + 2 - 1 + 2
= -2 + 2
= 0.
= > p(2) = 2(2)^4 - 5(2)^3 + 2(2)^2 - 2 + 2
= 32 - 40 + 8 - 2 + 2
= 0.
Therefore p(x) is divisible by x^2 - 3x + 2.
Hope this helps!
= > x^2 - 3x + 2
= > x^2 - 2x - x + 2
= > x(x - 2) - (x - 2)
= > (x - 1)(x - 2)
Now,
if p(1) and p(2) = 0, then p(x) is exactly divisible by f(x).
= > p(1) = 2(1)^4 - 5(1)^3 + 2(1)^2 - 1 + 2
= 2 - 5 + 2 - 1 + 2
= -2 + 2
= 0.
= > p(2) = 2(2)^4 - 5(2)^3 + 2(2)^2 - 2 + 2
= 32 - 40 + 8 - 2 + 2
= 0.
Therefore p(x) is divisible by x^2 - 3x + 2.
Hope this helps!
siddhartharao77:
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4
Hi,
Please see the attached file!
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Please see the attached file!
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