Question

Resolve into factors:2xy(2x+y)-8yz(y-8z)-32zx(x-4z)-32xyz

Answer 1

$4 x^{2}(y-16 z)+2 y 2(x-4 z)+8 z^{2}(y-16 x)-32 x y z$

Step-by-step explanation:

$\begin{aligned}&2 x y(2 x+y)-8 y z(y-8 z)-32 z x(x-4 z)-32 x y z\\&\begin{array}{l}2 x y(2 x)+2 x y(y)-8 y z(y)+8 y z(8 z)-32 z x(x)+32 z x) 4 z-32 x y z \\=4 x^{2} y+2 x y^{2}-8 z y^{2}+8 y z^{2}-64 z x^{2}+128 x z^{2}-32 x y z \\=4 x^{2} y-64 z x^{2}+2 x y^{2}-8 z y^{2}+8 y z^{2}+128 x z^{2}-32 x y z \\=4 x^{2}(y-16 z)+2 y 2(x-4 z)+8 z^{2}(y-16 x)-32 x y z\end{array}\end{aligned}$

To learn more

i)12x²+61x+77, Find the factors of the given polynomial

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ii)Find the number of factors for the polynomial f(x)=x^9-x

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