Question

root 3 -1 by root 3 + 1 =a-b root 3

Answer 1

heya..!!!!!


L.H.S

$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \\ \\ = > \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1 } \\ \\ = > \frac{3 + 1 - 2 \sqrt{3} }{3 - 1} \\ \\ = \frac{4 - 2 \sqrt{3} }{2} \\ \\ = \frac{2(2 - \sqrt{3}) }{2} = 2 - \sqrt{3}$
on comparing both side with R.H.S

we get,

2 - √3 = a - b√3

a = 2 , b = 1

Answer 2

Answer:

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