Samir can do a job in 15 days and dev can do the same job in 9 days. with the help of Ravi, they did the job in 3 days only. Then, Ravi alone can do the job in
Answers
Answer:
Let the number of days required for Abu to finish the job be x.
Then the number of days required for Babu to finish the job will be x+6.
That is, Abu finishes
x
1
part of the job and Babu finishes
x+6
1
part of the job in one day.
Thus, they can together finish
x
1
+
x+6
1
part of the job in one day.
Given that they can together finish the job in 4 days, we have
x
1
+
x+6
1
=
4
1
⇒
x(x+6)
(x+6)+x
=
4
1
⇒4(2x+6)=x
2
+6x
⇒8x+24=x
2
+6x
⇒x
2
−2x−24=0
⇒x
2
−6x+4x−24=0
⇒(x−6)(x+4)=0
⇒x=6 or x=−4
Here, x is number of days required for Abu to finish the job, so it is not a negative number.
Thus, x=−4 is inadmissible.
Hence, Abu requires 6 days and Babu requires x+6=6+6=12 days to finish the job alone.
Step-by-step explanation:
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Answer:
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