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Heya User,
--> sin θ = 3/5
=> cos θ = √ [ 1 - sin² θ ] = √ [ 1 - 9/25 ] = 4/5
=> cot θ = cosθ / sinθ = [
= 4/3 --> (i)
Also,
--> sec θ = 1/cosθ = 5/4 -------> (ii)
Adding (i) and (ii),
--> cot θ + sec θ = 4/3 + 5/4 = [ 16 + 15 ] / 12 = 31/12 <-- Desired Ans
--> sin θ = 3/5
=> cos θ = √ [ 1 - sin² θ ] = √ [ 1 - 9/25 ] = 4/5
=> cot θ = cosθ / sinθ = [
Also,
--> sec θ = 1/cosθ = 5/4 -------> (ii)
Adding (i) and (ii),
--> cot θ + sec θ = 4/3 + 5/4 = [ 16 + 15 ] / 12 = 31/12 <-- Desired Ans
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