show that a1,a2,....,an,... from an AP where an is defined as below (1) an=3+4n (2)=9-5n Also find the sum of the 15th terms in each case
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I) an=3+4n
if n=1,
a1=3+4(1)
=3+4
a1=7
if n=2
a2=3+4(2)
=3+8
a2=11
if n=3
a3=3+4(3)
=3+12
a3=15
a. p is. 7,11,15.... a=7,,, d=4
a15=a+(n-1)d
=7+(15-1)4
=7+(14)4
=7+56
a15=63
sum;
sn=n/2((2a+(n-1)d)
s15=63/2(2x7+(63-1)4)
=63/2(14+(62)4)
=63/2(14+248)
=63/2(262)
=63(131)
s15=8253
nithi57:
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