Question

Show the formation of O2, HCl, Cl2 and N2.

Answer 1

Answer:

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Answer 2

Answer:

Electron dot structure:

Electron dot structure shows the number of valence electrons in the in an element.

Formation of $\mathrm{O}_{2}$:

Each oxygen atom has six valence electrons , it requires only two electrons to get stable octet electronic configuration. Both are share each electron and get octet electronic configuration.

Formation of HCl:

Hydrogen and chlorine atoms each one shares one electron to get stable octet electronic configuration.

Formation of$\mathrm{Cl}_{2}$:

Each chlorine atoms shares one electron to get stable octet electronic configuration.

Formation of $\mathrm{N}_{2}$:

Each nitrogen atoms shares one electron to get stable octet electronic configuration.

The formation of $\mathrm{O}_{2}$, HCL,  $\mathrm{Cl}_{2}$, $\mathrm{N}_{2}$ are attached below respectively.