Math, asked by UdayMehtani1, 1 year ago

simplify this question

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Answered by kvnmurty

Answer is perhaps 4.

Let us call 8ⁿ = X.

8ⁿ⁺¹ = 8 * 8ⁿ = 8 X
2³ⁿ⁺¹ = 2³ⁿ * 2 = 2 * (2³)ⁿ = 2 * 8ⁿ = 2 X
2³ⁿ⁻² = 2³ⁿ /2² = 8ⁿ * 1/ 4

We substitute these in the given expression:

$\frac{6 (8)^{n+1}+16 (2)^{3n-2}}{10 (2)^{3n+1}- 7 (8)^n}\\\\=\frac{6 * 8 X + 16 * X * 1/4}{10*2*X-7*X}\\\\=\frac{52 X}{13 X}= 4$

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Answered by Anonymous

Heya User,

--> Let's see :-->

[tex] \frac{ 6(8)^{n+1} + 16(2)^{3n-2} }{ 10(2)^{3n+1} - 7(8)^n } \\\\ Converting\: every\: term\: in\: the\: form \: (8)^n \\ = \frac{ 48 (8)^n + 2^4 * (2)^{3n-2}}{ 20(2)^{3n} - 7(8)^n} \\ = \frac{48(8)^n + 4(2)^{3n}}{ 20(8)^n - 7(8)^n}\\ [/tex]
[tex]Putting (8)^n as \: x \: and \: solving\:our\:result:- \\\\ = [ 48x + 4x ] / [ 20x - 13x ] = 52x / 13x = 4 \\ And\:so,\:you\:get\:your \:answer.....[/tex]

kvnmurty: well done.

ABHAYSTAR: why sir

ABHAYSTAR: ????

kvnmurty: Ansh are you a brainly star? want to be?

kvnmurty: abhaystar. .I said the above answer was well written

ABHAYSTAR: ok sir

Anonymous: Sure Sir!

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