Question

Simplify x(2x^2-7x+3)and find the values for it i)x=1 ii)x=0

Answer 1

P(x) = X(2X²-7X+3)
P(1) = 1(2×(1)²-7×1+3)
= 1(2-7+3)
= 5-7 = -2
P(0) = 0(2×(0)²-7×0+3)
= 3

Answer 2

Answer:

1) 0    2)0

Step-by-step explanation:

1) x(2x^2-7x+3)

x=1  so,

1(2(1)^(2)-7(1)+3)

1(2(2)-7(1)+3)

1(4-7+3)

4-7+3= (-3)+3=0

2)  x ( 2x^2-7x+3)

x=0 so,

0(2(0)^(2) -7(0)+3)

if multiply any number with zero we get zero.

ans=0.