sin 43+cos 47+cos 47+sin 43=1.solve this without using tringnometric tables
Answers
Answered by
4
LHS: sin43+cos47+cos47+sin 43
= 2sin43+2cos47
= 2(sin43+cos47)
If A+B (43+47) = 90, then α=45
= 2 (sin²45)
= 2 (1/√2)²
= 2×1/2
= 1 ----------- RHS
therefore, Sin 43+cos 47+cos 47+sin 43=1
Hence it is proved.
= 2sin43+2cos47
= 2(sin43+cos47)
If A+B (43+47) = 90, then α=45
= 2 (sin²45)
= 2 (1/√2)²
= 2×1/2
= 1 ----------- RHS
therefore, Sin 43+cos 47+cos 47+sin 43=1
Hence it is proved.
himlu:
is this right answer
if yes so thanks
Similar questions