Math, asked by Aishwaryashrinivasan, 9 months ago

sin(90°-A)cosA/tanA+cos(90°-A)sinA/cotA

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Answered by shreyasen14

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Step-by-step explanation:

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sin(90°-A)cosA/tanA+cos(90°-A)sinA/cotA​

Answers

sin(90°-A)cosA/tanA+cos(90°-A)sinA/cotA