sin2theta\1+cos2theta
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12
Sin2theta/1+cos2theta x1-cos2theta/1-cos2theta =sin2theta(1-cos2theta) /1^2-cos^2.2theta =sin2theta(1-cos2theta) /sin2theta =1-cos2theta.... I hope this is the answer.. Please comment if i am right
keerthana27:
It's wrong the answer is tan theta
Answered by
39
sin2theta/1+cos2theta
sin2theta= 2sin theta costheta
cos2theta= cos^2theta - sin^2theta
= 2sinthetacostheta/ (sin^2theta+cos^theta+cos^2theta- sin^2theta)
=2sintheta/2cos^2theta
= sintheta/costheta
=tantheta
sin2theta= 2sin theta costheta
cos2theta= cos^2theta - sin^2theta
= 2sinthetacostheta/ (sin^2theta+cos^theta+cos^2theta- sin^2theta)
=2sintheta/2cos^2theta
= sintheta/costheta
=tantheta
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