Question

solution of question 12

Answer 1

let a-3d , a -d , a+d and a+3d are four part of 32

hence ,

a -3d + a - d +a +d + a +3d = 32

4a = 32

a = 8
again,

( a-3d)(a +3d)/(a-d)(a +d) = 7/15

(a^2 -9d^2)/(a^2 -d^2) = 7/15

15(a^2 -9d^2 ) =7(a^2 - d^2)

15a^2 -7a^2 = 135d^2 -7d^2

8a ^2 = 128d^2

a = +_4d

d = +_a/4 =+_(8/4) = +_ 2

hence,
four numbers ,
8 -6 , 8 -2 , 8 +2 , 8 +6
2 , 6 , 10 , 14

or numbers are ------

14 , 10, 6, 2