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Since no external force does any work on the earth ball system , thus the mechanical emergy of the system doesn't change.
at the start potential energy is zero and velocity u.
Ui+ Ki =Uf +Kf
thus
1/2mu²+0 = mg(100) + 0
applying the same law when ball is at top and after the time when it has 60% KE
mg100 + 0 = mgh +6/10(1/2*m*u²)
mg100-6/10mg100=mgh
h=4/10*100= 40m
at the start potential energy is zero and velocity u.
Ui+ Ki =Uf +Kf
thus
1/2mu²+0 = mg(100) + 0
applying the same law when ball is at top and after the time when it has 60% KE
mg100 + 0 = mgh +6/10(1/2*m*u²)
mg100-6/10mg100=mgh
h=4/10*100= 40m
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Answer - The Kinetic Energy will reduce to 60% at the height of 40m..
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