Solve for x
8x(52-x)=81x-32x²
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let start here we go
8x(52-x)=81x-32x²
step 1 :- in left hand side multiply the 8x to bracket
8x(52-x)=81x -32x²
416x - 8x² = 81x -32²
step 2 :- let the value of left hand side will put in right hand side i.e
0= 8x²- 416x + 81x -32²
0=8x² - 335x - 1024. (1024 come form {32²} 1024 is squre of 32)
8x2−335x−1024=0
Step 1: Use quadratic formula with a=8, b=-335, c=-1024.
x=
−b±√b2−4ac
2a
x=
−(−335)±√(−335)2−4(8)(−1024)
2(8)
x=
335±√144993
16
x=
335
16
+
1
16
√144993 or x=
335
16
+
−1
16
√144993
Answer:
x=
335
16
+
1
16
√144993 or x=
335
16
+
−1
16
√144993
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