Question

Solve. Sum no 8 please

Answer 1

Hey dear here is your answer!!!!!

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We would be applying the concept of properties of angles of a parallelogram and triangle to solve this question.

Here, ∠C = 80°

Also, ∠B is adjacent to ∠C.

So, ∠B = 180° - ∠C    (Adjacent Angles)

∠B = 180° - 80°

∠B = 100°

Also, ∠A is opposite to ∠C.

So, ∠A = 80°.    (Opposite Angles)

Now, bisector of ∠A would be - $\frac{80}{2}$

=40°

And bisector of ∠B would be - $\frac{100}{2}$

=50°

Let's see ΔAOB and apply angle sum property over here.

∠AOB + 50° + 40° = 180°   (Angle Sum Property)

∠AOB  + 90° = 180°

∠AOB = 180° - 90°

∠AOB = 90°

So, 90° is your answer !

❣️⭐ Hope it helps you dear...⭐⭐❣️❣️