Solve the 14th question.
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Answered by
2
35-33x+4x²
=4x²-33x+35
=4x²-(28+5)x+35
=4x²-28x-5x+35
=4x(x-7)-5(x-7)
=(4x-5)(x-7)
that's all
if it helped u just click thanks
=4x²-33x+35
=4x²-(28+5)x+35
=4x²-28x-5x+35
=4x(x-7)-5(x-7)
=(4x-5)(x-7)
that's all
if it helped u just click thanks
Answered by
1
Hey there !!!!!!!!!!!
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
P(x) = 4x²-33x+35
By using factorisation method
35*4x² =110x²= (-28x)(-5x) and -33x= -28x-5x
So,
P(x) = 4x²-33x+35
= 4x²-28x-5x+35
= 4x(x-7)-5(x-7)
=(4x-5)(x-7)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you.....................
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
P(x) = 4x²-33x+35
By using factorisation method
35*4x² =110x²= (-28x)(-5x) and -33x= -28x-5x
So,
P(x) = 4x²-33x+35
= 4x²-28x-5x+35
= 4x(x-7)-5(x-7)
=(4x-5)(x-7)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you.....................
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