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[0.4x+3y=1.2_____(I)]×2
[7x-2y=17/6_____(II)]×3
Multiplying equation (I) by 2 and equation (II) by 3,,
On adding equation one and two,,
0.8x+6y=2.4
21x-6y=(17/6)3
----------------
21.8x=2.4+17/2
=>21.8x=2.4+8.5
=>21.8x=10.9
=>x=10.9/21.8
=>x=(109×10)/(218×10)
=>x=109/218
=>x=1/2
Since,,Value of x on keeping in equation (I)
Hence,,
(0.4×1/2)+3y=1.2
=>(4/10)×(1/2)+3y=1.2
=>0.2+3y=1.2
=>3y=1.2-0.2
=>3y=1
=>y=1/3
The value of,, x=1/2
& The value of,,y=1/3,,,Ans....
Hope it helps you...plz mark it as Brainliest answer.. Thanks Mate...
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