Question

solve the following 1) find the side and perimeter of a square whose diagonal is 10 cm​

Answer 1

Answer:

mark as brain list please

Step-by-step explanation:

It is given that ABCD is a square.

∴ AB = BC = CD = DA = a (say)

According to Pythagoras theorem, in ∆ABD

AB2+AD2=BD2

⇒a2+a2=102

⇒2a2=100

⇒a2=50

⇒a=50

⇒a=52cm

Hence, the side of the square is 5

2

cm.

Now,

Perimeter of a square =

4×(side)

=

4×a

=

4×52

=

202

cm

Hence, the perimeter of the square is 20

2

cm

Answer 2

Answer:

Side = 10/√2

Perimeter = 20√2

Step-by-step explanation:

The full explanation is given in the photo attached above.