solve the following 1) find the side and perimeter of a square whose diagonal is 10 cm
Answers
Answered by
3
Answer:
mark as brain list please
Step-by-step explanation:
It is given that ABCD is a square.
∴ AB = BC = CD = DA = a (say)
According to Pythagoras theorem, in ∆ABD
AB2+AD2=BD2
⇒a2+a2=102
⇒2a2=100
⇒a2=50
⇒a=50
⇒a=52cm
Hence, the side of the square is 5
2
cm.
Now,
Perimeter of a square =
4×(side)
=
4×a
=
4×52
=
202
cm
Hence, the perimeter of the square is 20
2
cm
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Answered by
2
Answer:
Side = 10/√2
Perimeter = 20√2
Step-by-step explanation:
The full explanation is given in the photo attached above.
Attachments:
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