Question

Solve the following 7x²+ 5x + 9

Answer 1

Answer:

No real roots.

Step-by-step explanation:

As D (b² -4ac)  <0

Therefore there are no real solutions.

Answer 2

The solution is $x=\frac{-5+\sqrt{227}i}{14},\frac{-5-\sqrt{227}i}{14}$

Step-by-step explanation:

Given : Quadratic equation $7x^2+5x+9$

To find : Solve the quadratic equation ?

Solution :

Quadratic equation $7x^2+5x+9=0$

Solve the quadratic equation $ax^2+bx+c=0$ by quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=7, b=5 and c=9

Substitute the values,

$x=\frac{-5\pm\sqrt{5^2-4(7)(9)}}{2(7)}$

$x=\frac{-5\pm\sqrt{25-252}}{14}$

$x=\frac{-5\pm\sqrt{-227}}{14}$

$x=\frac{-5\pm\sqrt{227}i}{14}$

$x=\frac{-5+\sqrt{227}i}{14},\frac{-5-\sqrt{227}i}{14}$

Therefore, the solution is in complex form i.e. $x=\frac{-5+\sqrt{227}i}{14},\frac{-5-\sqrt{227}i}{14}$

#Learn more

Solve the following equation :

7x-5=2x

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