Question

solve the following equation by trial and error

method=

5p+2=17

Answer 1

Answer:

5p=17-2

5p=15

p=15/5

p=3

Answer 2

Correct question:-

Solve the following equations by trial and error method:

(i) 5p + 2 = 17

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$\bold{STEP-BY-STEP-EXPLANATION:}$

LHS = 5p + 2

By substituting the value of p = 0

Then,

LHS = 5p + 2

= (5 × 0) + 2

= 0 + 2

= 2

By comparing LHS and RHS

2 ≠ 17

Therefore,LHS ≠ RHS

Hence, the value of p = 0 is not a solution to the given equation.

Let, p = 1

LHS = 5p + 2

= (5 × 1) + 2

= 5 + 2

= 7

By comparing LHS and RHS

7 ≠ 17

Therefore,LHS ≠ RHS

Hence, the value of p = 1 is not a solution to the given equation.

Let, p = 2

LHS = 5p + 2

= (5 × 2) + 2

= 10 + 2

= 12

By comparing LHS and RHS

12 ≠ 17

Therefore,LHS ≠ RHS

Hence, the value of p = 2 is not a solution to the given equation.

Let, p = 3

LHS = 5p + 2

= (5 × 3) + 2

= 15 + 2

= 17

By comparing LHS and RHS

17 = 17

Therefore, LHS= RHS

Hence, the value of p = 3 is a solution to the given equation.