Question

Solve the following quadratic equations by factorization:x²-(√2+1)x+√2=0

Answer 1

Plz refer to the pic my frnd....

Answer 2

X = 1, √2

Step-by-step explanation:

x²-(√2+1)x +√2 = 0

Factors of +√2 are -√2 and -1.

So x²-(√2+1)x +√2 = 0 can be written as:

x² -√2x -x +√2 = 0

x (x -√2) -1 (x -√2) = 0

(x - 1) (x -√2) = 0

So the factors are (x - 1) and (x -√2).

If x - 1 = 0, then x = +1

If x -√2 = 0, then x = +√2

Hence solved.

X = 1, √2