Question

Solve the numerical:
1. A solid weighs 30 gf in air and 20 gf in water. Find how much will it weigh when
immersed in a liquid of relative density 0.9?
​

Answer 1

Make Me Brainlist

Hope you like

Answer 2

Given: Solid weighs 30 gf in air and 20 gf in water.

To find: Weight of solid when immersed in a liquid of relative density 0.9.

Solution:

• Loss of the weight of the solid in liquid is equal to the weight of the liquid displaced.

• Weight of solid in air, W₁ = 30 gf.
• Weight of solid in water, W₂ = 20 gf.
• Volume of solid is given by mass divided by density of  the solid.

        $Volume = \frac{30}{10} m^{3}$

                      $= 3m^{3}$

• Relative density of solid is given by,

       $(R. D.)_{solid} = \frac{W_{1} }{W_{1} - W_{2} } * (R.D.)_{water}$

                         $= \frac{30}{30 - 20} * 1$

                         $= 3$  

• Weight of solid in liquid of relative density 0.9 = W₃

        $3 = \frac{30}{30 - W_{3} } * 0.9$

        $W_{3} = 30 - (\frac{30}{3} * 0.9 )$

              $= 21gf$

Therefore, the solid will weigh 21 gf when immersed in a liquid of relative density 0.9.