solve the quadratic equation
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x^2+3x+2=0
By splitting middle term method
x^2+x+2x+2=0
x(x+1)+2(x+1)=0
(x+1)(x+2)=0
x+1=0 or x+2=0
x=-1 or x=-2
nikhil33313:
bohot easy tha na
Answered by
1
x²+3x+2
x²+(2+1)x+2
x²+2x+1x+2
x(x+2x) + 1(x+2)
(x+2x) (x+1)
x²+(2+1)x+2
x²+2x+1x+2
x(x+2x) + 1(x+2)
(x+2x) (x+1)
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