Question

solve the simultaneous equation.(guy's plz help)​

Answer 1

$\bf\large\blue{Question\::-}$

• Solve the linear equation :-

$y - 6 = \frac{1}{6} x$

$\frac{3}{4} x = 1 + y$

$\bf\large\blue{Solution\::-}$

$y - 6 = \frac{1}{6} x$

$\implies 6(y - 6) = x$

$\implies6y - 36 = x$

$\implies6y - x = 36 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ... \: (i)$

$\frac{3}{4} x = 1 + y$

$\implies3x = 4(1 + y)$

$\implies3x = 4 + 4y$

$\implies4y - 3x = - 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ... \: (ii)$

$\star$ Now, multiplying equation (i) by 3.

$18y - 3x = 108 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:... \: (iii)$

$\star$ Now, substracting equation (ii) from equation (iii)

we get :-

$1</em><em>4</em><em>y = 112$

$\implies \: y = </em><em>8</em><em>$

$\star$ Now, Substituting the value of y in equation (i) :-

$6y - x = 36$

$\implies4</em><em>8</em><em> - x = 36$

$\implies x = </em><em>1</em><em>2</em><em>$

$\bf\large\blue{Answer\::-}$

• Value of x is 12.
• Value of y is 8.