Question

Solve this 24th que.................

Answer 1

hello mate here is Ur answer

given : atomic mass if boron is 10.81

and the atomic mass of boron that is in abundant is 11.01

the we know that

B1+B2÷2= B ====(1)

here B1 refers to the atomic mass of the 1st boron isotope and B2 the 2nd isotope and
B is the common atomic mass of boron here we need to find the mass of 2nd Boron isotope

from equation 1
we get to know that

B1+B2= 2B

11.01+B2= 2×10.81

11.01+B2=21.62

B2= 21.62-11.01= 10.01

hence 10.01 is the mass of 2nd boron isotope

hope it helps u

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