solve this plzz! I will mark you as brainliest
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1
x+2=0 ,x=-2.
3 (-2)^3-4x^2+21.
3×(-8)-4×4+21.
-24-16+21=-19.
3 (-2)^3-4x^2+21.
3×(-8)-4×4+21.
-24-16+21=-19.
hiteshpal:
p (x)= -2 se hi dusra bhi hoga
Kindly solve it step by step..
Answered by
3
Given f(x) = x^3 + 3x^2 + 5x + 6.
Given g(x) = x + 2.
By remainder theorem,
= > x + 2 = 0
= > x = -2.
Plug x = -2 in f(x), we get
= > (-2)^3 + 3(-2)^2 + 5(-2) + 6
= > -8 + 12 - 10 + 6
= > -6 + 6
= > 0.
Therefore the remainder is 0.
Hope this helps!
Given g(x) = x + 2.
By remainder theorem,
= > x + 2 = 0
= > x = -2.
Plug x = -2 in f(x), we get
= > (-2)^3 + 3(-2)^2 + 5(-2) + 6
= > -8 + 12 - 10 + 6
= > -6 + 6
= > 0.
Therefore the remainder is 0.
Hope this helps!
where
in your questions section
https://brainly.in/question/4050424
is it root 75 (or) root 78 in the 1st questions denominator?
78
Thanks..
thank u bhaiya
for solving
My pleasure..
ok
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