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Answer:
1/z = 1/x + 1/y
Step-by-step explanation:
2 = k^1/x
3 = k^1/y
6 = k^1/z
2 x 3 = 6
k^1/x * k^1/y = k^1/z
1/x + 1/y = 1/y
Hence Proved
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