Question

solve x

7^3/7^x-2=7^7

Answer 1

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Answer 2

${7}^{3} \div {7}^{x - 2} \: = \: {7}^{7} \\ so \: \: {7}^{3 - (x - 2)} = {7}^{7} \\ comparing \: powers \: of \: 7 \\ from \: both \: sides \\ \: 3 - (x - 2) \: = \: 7 \\ 3 - x + 2 = 7 \\ x = 5 - 7 \\ x = - 2$


Power can be equated, if they have a common base.
Like mentioned below, as an example:

${x}^{y} = {x}^{3} \\ so \: on \: comparing \: powers \\ y = 3$

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