some one plz solve..............
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get guaranteed answer in rd sharma class 9 pg 8.38
hope it helps
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Hey!
It's pretty simple!
Look It's already given that PQ & RS are parallel
So now you know that the angle between the reflected ray and the incident ray is always equal. So applying this, imagine the normal at B and normal at C , You will get that Angle (ABC) = Angle (BCD) ...
Now the property of parallel lines...
i.e If a pair of alternate interior angles are equal then they are parallel ...
So we already found that Angle (ABC) = Angle (BCD) [Alternate interior angles]
So this proves that ABIICD ...
*EDIT*
For those who don't know how to prove Angle(ABC) = Angle (BCD) ... Here you go... As you consider the normal let it be BM &CN ...
You will get as BM⟂PQ and CN⟂RS ....
BM and CN will be parallel to each other (both 90 degrees and lie between parallel lines). So BM and CN be parallel and BC be the transversal...
You will get Angle(ABC) = Angle (BCD) Hope it helps!!
Good Luck
It's pretty simple!
Look It's already given that PQ & RS are parallel
So now you know that the angle between the reflected ray and the incident ray is always equal. So applying this, imagine the normal at B and normal at C , You will get that Angle (ABC) = Angle (BCD) ...
Now the property of parallel lines...
i.e If a pair of alternate interior angles are equal then they are parallel ...
So we already found that Angle (ABC) = Angle (BCD) [Alternate interior angles]
So this proves that ABIICD ...
*EDIT*
For those who don't know how to prove Angle(ABC) = Angle (BCD) ... Here you go... As you consider the normal let it be BM &CN ...
You will get as BM⟂PQ and CN⟂RS ....
BM and CN will be parallel to each other (both 90 degrees and lie between parallel lines). So BM and CN be parallel and BC be the transversal...
You will get Angle(ABC) = Angle (BCD) Hope it helps!!
Good Luck
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For those who don't know how to prove Angle(ABC) = Angle (BCD) ...
Here you go...
As you consider the normal let it be BM &CN ....You will get as BM⟂PQ and CN⟂RS .... BM and CN will be parallel to each other (both 90 degrees and lie between parallel lines). So BM and CN be parallel and BC be perpendicular... You will get Angle(ABC) = Angle (BCD) Hope it helps!!
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