Math, asked by saadde, 1 year ago

subtract the sum of 2a+3b,a-2b+c,-a+2b and 4a +2b - 5 from6a-4b+8 solve


ganesh1271: answer is 9b + c -13

Answers

Answered by BrainlyKing5
32
HEY MATE HERE IS UR ANSWER

2a + 3b + a- 2b +c -a + 2b + 4a +2b -5

NOW COMPARING LIKE TERMS WE HAVE

(2a + a -a + 4a ) + (3b -2b + 2b + 2b ) -5

= 6a + 5b - 5

NOW WE NEED TO SUBTRACT THIS FROM 6a - 4b + 8

there for we have

6a -4b + 8 - ( 6a + 5b -5

= 0+ 9b + 13

= 9b + 13


HOPE ITS HELPFUL IF YES PLEASE MARK AS BRAINLIEST

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Answered by starbhalla565
16

                2a+3b+a-2b+c-a+2b+4a+2b-5

=               6a+5b+c-5

then sub from 6a -4b+8.

                 ( 6a-4b+8) - ( 6a+5b+c-5)

=                   6a-6a-4b-5b+8+5-c

=                  -9b-c+13

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