Sum of the digits of a two digit number is 11 when we interchange the digits it is found that the resulting new number is greater than the original by 63 . Find the 2 digit number
Please solve it for 13 points.....
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Let x = ones digit
y = tens digit
Equation 1: x + y = 11
For equation 2,
(10x+y) = (10y+x) + 63
9x - 9y = 63
x = 9
y = 2
The original number is 29.
if you reverse it, it's 92 which is 29 + 63.
y = tens digit
Equation 1: x + y = 11
For equation 2,
(10x+y) = (10y+x) + 63
9x - 9y = 63
x = 9
y = 2
The original number is 29.
if you reverse it, it's 92 which is 29 + 63.
Booklover1338:
Thanks a lot.......was stuck on it forever !!!!
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