Question

Sum of zeros of x^2-3 is?

Answer 1

sum of Zeros = alpha+beata = -b/a = 0/1 = 0 Ans
product of the Zeros = -c/a = -(-3)/1 = 3Ans

Answer 2

So To find the zeros of the given equation , put x^2-3=0

now x^2=3

or x = +√3

Now taking the sum of zeros

Add them

√3 + (-√3) = 0

Hence Sum is Zero