Sum of zeros of x^2-3 is?
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sum of Zeros = alpha+beata = -b/a = 0/1 = 0 Ans
product of the Zeros = -c/a = -(-3)/1 = 3Ans
product of the Zeros = -c/a = -(-3)/1 = 3Ans
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So To find the zeros of the given equation , put x^2-3=0
now x^2=3
or x = +√3
Now taking the sum of zeros
Add them
√3 + (-√3) = 0
Hence Sum is Zero
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