surface area of a cuboid is 200 CM square and its lateral surface area is 140 CM square find the area of its base
piyush66152:
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T.S.A of cuboid =2(lb + bh+lh) = 200 m²
L.S.A = 2h( l+b) = 140 m²
The base area = lb
140 = 2h ( l+b)
140/2 = h(l +b)
70 = h( l+b).................(i)
200 = 2(lb + bh+ lh)
100 = lb + bh + lh
100 = lb + h( l + b)
100 = lb + 70................Putting the value from eq(i)
lb = 100 - 70
lb = 30 m²
∴ Area of the base = 30m²
L.S.A = 2h( l+b) = 140 m²
The base area = lb
140 = 2h ( l+b)
140/2 = h(l +b)
70 = h( l+b).................(i)
200 = 2(lb + bh+ lh)
100 = lb + bh + lh
100 = lb + h( l + b)
100 = lb + 70................Putting the value from eq(i)
lb = 100 - 70
lb = 30 m²
∴ Area of the base = 30m²
Answered by
0
Answer:
T.S.A = 200CM square
L.S.A = 140 CM square
AREA OF BASE
=140 = 2H(L+b)
=140/2 = h(l+b)
= 70=h(l+b)
200=2(lb+bh+hl)
200/2 = (bl+bh+hl)
100 = Lb + h(l+b)
100= lb +100
lb= 100-70
lb= 30 square
AREA OF BASE = 30 CM SQUARE
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