(Tan 46 degree )( tan 14 degree ) - ( Tan 74 degree )( Tan 14 degree ) + ( Tan 74 degree )( Tan 46 Degree ).
Answers
Answered by
0
Given :- Tan 46 degree )( tan 14 degree ) - ( Tan 74 degree )( Tan 14 degree ) + ( Tan 74 degree )( Tan 46 Degree ) ?
Solution :-
→ tan 46° * tan 14° - tan 74° * tan 14° + tan 74° * tan 46°
using :-
- tan A * tan B = 1 - [(tan A + tan B )/tan (A+B)] => In tan 46° * tan 14° and tan 74° * tan 46°
- tan A * tan B = [(tan A - tan B) / tan (A - B)] - 1 => In tan 74° * tan 14°
so,
→ 1 - {(tan 46° + tan 14°)/tan 60°} - [{(tan 74° - tan 14°)/tan 60°} - 1] + 1 - {(tan 74° + tan 46°)/tan 120°}
using :-
- tan 60° = √3
- tan 120° = - √3
then,
→ (1 + 1 + 1) + (- tan 46° - tan 14° - tan 74° + tan 14° + tan 74° + tan 46°) / √3
→ 3 + 0
→ 3 (Ans.)
Learn more :-
prove that cosA-sinA+1/cos A+sinA-1=cosecA+cotA
https://brainly.in/question/15100532
help me with this trig.
https://brainly.in/question/18213053
Similar questions