tan3θ − 1/3 tan θ − 1=
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1
Step-by-step explanation:
Given, tan2θ.tanθ=1
Since tan3θ=
1−tanθ.tan2θ
tanθ+tan2θ
⇒tan3θ→∞
i.e. 3θ=
2
(2n+1)π
i.e. θ=
6
(2n+1)π
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