Math, asked by airafrost, 1 year ago

ten cards with number 1 to 10 written on them are placed in a bag. A card is chosen from the bag at random is : (1) 7 (2) 9 or 10 (3) a number greater than 4 (4) a number less than 6 (probability)​

Answers

Answered by deepanjalipande67
2
n(S)=10


1) Let A be the probability that the number drawn is 7
n(A)=1
P(A)=n(A)/n(S)

P(A)=1/10


2)Let B be the probability that the number drawn is 9 or 10
n(B)=2
P(B)=n(B)/n(S)
P(B)=2/10
the
P(B)=1/5


3)Let C be the probability that the number drawn is greater than 4.
n(C)=6
P(C)=n(C)/n(S)
P(C)=6/10

P(C)=3/5

4)Let D be the probability that the number drawn is less than 6.
n(D)=5
P(D)=n(D)/n(S)
P(D)=5/10

P(D)=1/2




Hope this helps you dear !!!!

✌✌

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