Question

$7x^{2}+77x+210=0$

Answer 1

Hello !!

Find the coeficients of the equation.

A = 7 ; B = 77 ; C = 210

Find the discriminant.

D = b^2 - 4ac

D = 77^2 - 4 × 7 × 210

D = 5929 - 5880

D = 49

Find the roots of the equation.

x = (-b ± √D)/(2a)

x = (-77 ± √49)/(2 × 7)

x = (-77 ± 7)/14

x' = (-77 + 7)/14

x' = -70/14

x' = -5

x'' = (-77 - 7)/14

x'' = -84/14

x'' = -6

Final result : the solution for quadratic equation is -5 and -6.

I hope I have collaborated !