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11Cr ( a x^2)^ 11-r (1/bx)^r
11Cr a^11-r x^22-2r ( b^ -r) x^-r
11Cr a^11-r b^-r x^22-3r
22-3r = 7.
3r = 15
r= 5
11C5 a^6 b^-5
11Cr a^11-r x^22-2r ( b^ -r) x^-r
11Cr a^11-r b^-r x^22-3r
22-3r = 7.
3r = 15
r= 5
11C5 a^6 b^-5
Anonymous:
Thanks
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Answer:
r= 5 please mark me brainliest
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