Math, asked by Anonymous, 11 months ago

 <h4>REFER THE ATTACHMENT. </h4>

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Answered by Anonymous
2
11Cr ( a x^2)^ 11-r (1/bx)^r

11Cr a^11-r x^22-2r ( b^ -r) x^-r

11Cr a^11-r b^-r x^22-3r

22-3r = 7.

3r = 15

r= 5

11C5 a^6 b^-5

Anonymous: Thanks
Answered by saritakabra0406
0

Answer:

r= 5 please mark me brainliest

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