Math, asked by siddarth29, 1 year ago


 {y}1 + 3 {x}^{2}  {y}^{2}  = 0
solve the equation

Answers

Answered by rakeshmohata
1
Hope u like my process
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 =  >y_{1} + 3 {x}^{2}  {y}^{2}  = 0 \\  \\  =  >  \frac{dy}{dx}  =  - 3 {x}^{2}  {y}^{2}  \\  \\  =  > 3 {x}^{2}dx =   -  \frac{dy}{ {y}^{2} }   \\  \\  =  > 3 \int {x}^{2} dx =  -  \int \frac{dy}{ {y}^{2} }  \\  \\  =  > 3( \frac{ {x}^{3} }{3} )  =  - ( -  \frac{1}{y} ) + c \\  \\  =  >  {x}^{3}  =  \frac{1}{y}  + c
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This is ur required general solution.
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Hope this is ur required answer

Proud to help you

siddarth29: thnq so much
rakeshmohata: welcome..
siddarth29: need more help sir
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