Question

${y}1 + 3 {x}^{2} {y}^{2} = 0$
solve the equation

Answer 1

Hope u like my process
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$= >y_{1} + 3 {x}^{2} {y}^{2} = 0 \\ \\ = > \frac{dy}{dx} = - 3 {x}^{2} {y}^{2} \\ \\ = > 3 {x}^{2}dx = - \frac{dy}{ {y}^{2} } \\ \\ = > 3 \int {x}^{2} dx = - \int \frac{dy}{ {y}^{2} } \\ \\ = > 3( \frac{ {x}^{3} }{3} ) = - ( - \frac{1}{y} ) + c \\ \\ = > {x}^{3} = \frac{1}{y} + c$
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This is ur required general solution.
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