Math, asked by gthakral326, 1 year ago

The amount of air present in cylinder when a vacuum pump removes 1/2 of the air remaining in cylinder at a time

Answers

Answered by ShivdeepKaushal
1

Answer:

1:explain the question carefully

Answered by Anonymous
4

ʟᴇᴛ ᴀ ʙᴇ ᴛʜᴇ ᴀᴍᴏᴜɴᴛ ᴏғ ᴀɪʀ ɪɴɪᴛɪᴀʟʟʏ ᴀᴍᴏᴜɴᴛ ᴏғ ᴀɪʀ ʀᴇᴍᴀɪɴɪɴɢ ᴀғᴛᴇʀ 1sᴛ ᴘᴜᴍᴘ =ᴀ –(ᴀ/4)=3ᴀ/4

ᴀᴍᴏᴜɴᴛ ᴏғ ᴀɪʀ ʀᴇᴍᴀɪɴɪɴɢ ᴀғᴛᴇʀ 2ɴᴅ  ᴘᴜᴍᴘ= (3ᴀ/4) – (1/4)(3ᴀ/4)=9ᴀ/16

ᴀᴍᴏᴜɴᴛ ᴏғ ᴀɪʀ ʀᴇᴍᴀɪɴɪɴɢ ᴀғᴛᴇʀ 3ʀᴅ  ᴘᴜᴍᴘ= (9ᴀ/16) – (1/4)(9ᴀ/16)=27ᴀ/64

sᴏ ᴛʜᴇ sᴇʀɪᴇs ɪs ʟɪᴋᴇ

ᴀ,3ᴀ/4,9ᴀ/4,27ᴀ/64……..

ᴅɪғғᴇʀᴇɴᴄᴇ ɪsᴛ ᴀɴᴅ sᴇᴄᴏɴᴅ ᴛᴇʀᴍ=-ᴀ/4

ᴅɪғғᴇʀᴇɴᴄᴇ ʙᴇᴛᴡᴇᴇɴ sᴇᴄᴏɴᴅ ᴀɴᴅ ᴛʜɪʀᴅ ᴛᴇʀᴍ= -3ᴀ/16

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