The angle of elevation of a tower is observed to be 60 degree at the end of a horizontal base of 120 M measured from its bottom. Calculate the height of the tower.
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Height of the tower is 120√3m ie 207.84m
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Hey Mate !!
here is your answer !!
the angle of elevation of tower is 60°
and
base = 120 m
now , tan 60 ° = perpendicular / base =. height of tower / distance to horizontal base
{ tan 60 ° = √ 3 }
=> √3 = height of tower / 120 m
hence , height of tower is => √ 3 × 120m
hope it helps you dear !!!
thanks !!
here is your answer !!
the angle of elevation of tower is 60°
and
base = 120 m
now , tan 60 ° = perpendicular / base =. height of tower / distance to horizontal base
{ tan 60 ° = √ 3 }
=> √3 = height of tower / 120 m
hence , height of tower is => √ 3 × 120m
hope it helps you dear !!!
thanks !!
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