Question

The angle of elevation of the top of a tower from a point on ground which is 30 mts. Away from the foot of the tower is 30 degrees. Height of the tower is

Answer 1

let height of tower be x
height = tan 30 degree=x/30

:-1/root 3=x/30
root 3 x =30

Answer 2

Step-by-step explanation:

In ∆ ABC,

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.