Question

The area of a trapezium is 248square meter and its height is 8m. if one of parallel side is smaller than the other by 4m, find two parallel sides.

Answer 1

Let the larger parallel side= xm so ATQ smaller parallel side will be=(x-4)m
Height= 8m
Area of trapezium = 248m²

now,
Area of trap. = 1/2 (sum of parallel side)xheight
248 = 1/2 (x+x-4)8
248/4 =2x-4
62+4 = 2x
66 =2x
x = 66/2
x = 33

so, larger parallel side is 33m
smaller is 33-4 =29m