Question

The area of an equilateral  us 81 √3 cm2. Its height is

(a) 9√3 cm (b) 6√3 cm (c) 18√3 cm (d) None​

Answer 1

Answer:

(a)9$\sqrt{3$

Step-by-step explanation:

area of equilateral triangle = $\sqrt{3}$$a^{2}$/4

therefore 81$\sqrt{3}$ = $\sqrt{3} a^{2} /4$

∴ $a=18$

height of equilateral triangle = $\sqrt{3} a/2$

∴ $height = \sqrt{3}$×18/2

height = 9$\sqrt{3}$

Answer 2

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Given :-

• Base = 48 cm
• Hypotenuse = 50 cm

Find :-

• The area of triangle = ?

Solution :-

As we know,

Area of triangle = 1/2 × b × h

Now,

Find its height

Let the height be x

${h}^{2} = {p}^{2} + {b}^{2}$

${50}^{2} = {p}^{2} + {48}^{2}$

$196= {x}^{2}$

$\sqrt {196}= x$

14= h

Height = 14

Putting values in formula

= 1/2 × 48 × 14

= 48 × 7

= 336

Therefore option c)336 cm

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