the area of trapezium is 12 square metre in feet height be 3 M find the sum of its parallel sides
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Answered by
2
A = 1/2 * (a+b) * h
12 = 1/2*(a+b) *3
12 = 3/2(a+b)
(a+b) = 12*2/3
(a+b) = 8 m
Hope it will help you
If it is correct, please mark me as the brainliest
12 = 1/2*(a+b) *3
12 = 3/2(a+b)
(a+b) = 12*2/3
(a+b) = 8 m
Hope it will help you
If it is correct, please mark me as the brainliest
Answered by
4
Hi friend
-----------------
Your answer
---------------------
Area of trapezium = 1/2 × sum of parallel sides × height
Let the sum of parallel sides be x.
Then,
----------
1/2× x × 3 = 12
=> x = (12×2)/3
=> x = 8
Therefore, sum of parallel sides of the trapezium = 8 m
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
-----------------
Your answer
---------------------
Area of trapezium = 1/2 × sum of parallel sides × height
Let the sum of parallel sides be x.
Then,
----------
1/2× x × 3 = 12
=> x = (12×2)/3
=> x = 8
Therefore, sum of parallel sides of the trapezium = 8 m
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
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